通达信公式 n天内最大的n个 量累加 公式

2024-05-13 09:14

1. 通达信公式 n天内最大的n个 量累加 公式

这个公式的东西基本是透明和公开的,实际运用中没太大意义。 在趋势好时任何公式你发现都是对的,趋势不好时所有技术在破位后都处于失效状态。
    啥是趋势呢,显然是不会公开的东西也不会给大多数人知道这才是重点的重点。

通达信公式 n天内最大的n个 量累加 公式

2. 通达信怎么实现指标累加功能

老兄,就是几连板吧,对不!
公式如下:
a1:=c>=ref(c,1)*1.095 and c=h;

次数:BARSLASTCOUNT(a1);

3. 通达信公式问题

5  4   3 里面的第二大值????
第二大值:REF(FINDHIGH(H,0,3,2),3);
-----------------------------------------
你先将这句做成主图看看,然后你再决定什么条件下做出标记 
-----------------------------------------------------
做公式千变万化,不是什么教程能说清楚的 
有问题可以HI我

通达信公式问题

4. 通达信股票每天的涨幅加起的公式应该怎么写?

一楼哥们的累加是从上市之日起开始的,稍作修改就可以,把0改成3,表示3日来涨跌幅累加。
涨跌幅:=(C/REF(C,1)-1)*100;
涨跌和:SUM(涨跌幅,3);

5. 通达信指标编写小问题

直接送你一个
DIFF:EMA(CLOSE,12)-EMA(CLOSE,26);
DEA:EMA(DIFF,9);
MACD:2*(DIFF-DEA),COLORSTICK;
MACD1:2*(DIFF-DEA);
STICKLINE(MACD0,0,MACD,0,0),COLORGREEN;
STICKLINE(MACD>REF(MACD,1) AND MACD<0,0,MACD,0,0),COLORMAGENTA;
JCCOUNT:=COUNT(CROSS(DIFF,DEA),BARSLAST(DEA>=0));
金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=1,21)=1;
STICKLINE(金叉,0,0.1,5,0),COLOR0000FF;
DRAWTEXT(金叉,-0.095,'金叉'),COLOR0000FF;
二金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=2,21)=1;
STICKLINE(二金叉,0,0.15,5,0),COLORLIRED;
DRAWTEXT(二金叉,0.23,'二次金叉'),COLORLIRED;
三金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=3,28)=1;
STICKLINE(三金叉,0,0.2,5,0),COLORLIGREEN;
DRAWTEXT(三金叉,0.28,'三次金叉'),COLORLIGREEN;
四金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=4,28)=1;
STICKLINE(四金叉,0,0.25,5,0),COLORCYAN;
DRAWTEXT(四金叉,0.33,'四次金叉'),COLORCYAN;
五金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=5,33)=1;
STICKLINE(五金叉,0,0.3,5,0),COLORBLUE;
DRAWTEXT(五金叉,0.37,'五次金叉'),COLORBLUE;
六金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=6,33)=1;
STICKLINE(六金叉,0,0.35,5,0),COLORYELLOW;
DRAWTEXT(六金叉,0.0.7,'黄金底'),COLORYELLOW;
DRAWTEXT(六金叉,0.42,'六次金叉'),COLORYELLOW;
七金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=7,33)=1;
STICKLINE(七金叉,0,0.4,5,0),COLORWHITE;
DRAWTEXT(七金叉,0.0.88,'白金底'),COLORWHITE;
DRAWTEXT(七金叉,0.47,'七次金叉'),COLORWHITE;
八金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=8,33)=1;
STICKLINE(八金叉,0,0.5,5,0),COLORMAGENTA;
DRAWTEXT(八金叉,0.0.8,'钻石底'),COLORMAGENTA;
DRAWTEXT(八金叉,0.57,'八次金叉'),COLORMAGENTA;
九金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=9,33)=1;
STICKLINE(九金叉,0,0.55,5,0),COLORRED;
DRAWTEXT(九金叉,0.0.8,'金钻底'),COLORRED;
DRAWTEXT(九金叉,0.6,'九次金叉'),COLORRED;
A1:=BARSLAST(REF(CROSS(DIFF,DEA),1));
底背离:=(REF(L,A1+1)>L OR REF(C,A1+1)>C) AND (L,DIFF)>REF((L,DIFF),A1+1) AND CROSS(DIFF,DEA);
STICKLINE(底背离,0,-0.1,5,0),COLORRED;
DRAWTEXT(底背离,DEA,'底背离')COLORRED;
DRAWLINE(A1=0,DEA,底背离,DEA,0),COLOR0000FF,LINETHICK2;
A2:=BARSLAST(REF(CROSS(DEA,DIFF),1));
顶背离:=(REF(C,A2+1)(H,DIFF) AND CROSS(DEA,DIFF);
DRAWLINE(A2=0,DEA,顶背离,DEA,0),COLORFF00FF,LINETHICK2;
STICKLINE(顶背离,0,0.1,5,0),COLORGREEN;
DRAWTEXT(顶背离,DEA,'顶背离')COLORGREEN;
DRAWTEXT(CROSS(DIFF,DEA) AND 二金叉 AND 底背离,0.3,'三全底'),COLOR0000FF;
IF(DIFF>DEA,DIFF,DRAWNULL),COLORWHITE,LINETHICK2;
IF(DEA>REF(DEA,1) AND DIFF>DEA,DEA,DRAWNULL),COLORYELLOW,LINETHICK2;

{涨停100%}
T:=IF((BARSCOUNT(C) > 7),(100)*((MA(C,7))/(LLV(MA(C,7),7)) - 1),1);
N:=IF((T > 0.35),6,65);
W:=((-((100)*(HHV(H,N) - C))/(HHV(HIGH,N) - LLV(L,N))));
RV:=(CLOSE-LLV(LOW,27))/(HHV(HIGH,27)-LLV(LOW,27))*100;
RG:=(CLOSE-LLV(LOW,5))/(HHV(HIGH,5)-LLV(LOW,5))*100;
J0:=(HIGH+LOW)/2;
QJ:=EMA(J0,3);
J1:=IF(CLOSE>QJ,VOL,0);
J2:=IF(CLOSE<QJ,VOL,0);
BB:=MA(SUM(J1-J2,22),3);
累加:=21*BB+20*REF(BB,1)+19*REF(BB,2)+18*REF(BB,3)+17*REF(BB,4)
+16*REF(BB,5)+15*REF(BB,6)+14*REF(BB,7)+13*REF(BB,8)+12*REF
(BB,9)+11*REF(BB,10)+10*REF(BB,11)+9*REF(BB,12)+8*REF(BB,13)
+7*REF(BB,14)+6*REF(BB,15)+5*REF(BB,16)+4*REF(BB,17)+3*REF
(BB,18)+2*REF(BB,19)+REF(BB,20);
WMA1:=累加/(21+1)/21*2;
CC:=WMA1;
VAR3:=(BB-CC);VAR4:=SMA(RV,3,1);
VAR5:=SMA(VAR4,3,1);
KK:=EMA(SMA(RG,3,1),2);
DD:=SMA(KK,3,1);
涨停100%:CROSS(W,-2) AND CROSS(VAR4,VAR5) AND CROSS(KK,DD),COLORRED,LINETHICK1;

通达信指标编写小问题

6. 10天之内出现信号A,通达信选股公式如何编写?谢谢!

其实没必要这么算,并不需要算所有f[i][j],只要知道f[0][n-1]就可以了,对于所有j-i=const的i和j,这个值都是一样的。 
f(n)表示n个node可以有多少种不同的树,f(n) = f(0) * f(n-1) + f(1)*f(n-2) + ... + f(n-1)*f(0),也就是左边i个节点,右边n-i-1个节点,所有情况累加起来。 
  
【 在 liutaobit 的大作中提到: 】 
: Given n, how many structurally unique BST's (binary search trees) that store values 1...n? 
: For example, 
: Given n = 3, there are a total of 5 unique BST's. 
: ................... 
  
-- 
※ 修改:·Roseau 于 Oct  5 21:55:13 2013 修改本文·[FROM: 114.250.86.*]

7. 请高手编写通达信公式

.均线预警}
CROSS(CLOSE,MA(CLOSE,N)) OR CROSS(MA(CLOSE,N),CLOSE); 
{这个是股价上穿或下穿N日均线时的语句,新建一个条件选股公式,建公式的时候,把N作为参数填进参数表,最小,最大,缺省分别填上1,250,5,然后给公式取个名字保存起来。之后点开“条件预警”的设置项,将你建的公式选进去,再选上全部股票就可以做到你要的东西}

{2.均线附近选股}
RANGE(CLOSE,MA(CLOSE,N)*0.995,MA(CLOSE,N)*1.005);
{一样,新建一个选股公式,填好参数表,取个名字保存起来,就可以用了,这里帮你定义的“均线附近”是均线上下0.5%,你可以按你自己的想法去修改这个范围} 

{3.补充……你想预警6条均线,把语句复制6次,参数N改成N1,N2...N6,语句之间用OR 连接就行了}
CROSS(CLOSE,MA(CLOSE,N1)) OR CROSS(MA(CLOSE,N1),CLOSE) OR 
CROSS(CLOSE,MA(CLOSE,N2)) OR CROSS(MA(CLOSE,N2),CLOSE) OR 
CROSS(CLOSE,MA(CLOSE,N3)) OR CROSS(MA(CLOSE,N3),CLOSE) OR 
CROSS(CLOSE,MA(CLOSE,N4)) OR CROSS(MA(CLOSE,N4),CLOSE) OR 
CROSS(CLOSE,MA(CLOSE,N5)) OR CROSS(MA(CLOSE,N5),CLOSE) OR 
CROSS(CLOSE,MA(CLOSE,N6)) OR CROSS(MA(CLOSE,N6),CLOSE);

请高手编写通达信公式

8. 通达信怎么实现如下效果呢?

目前没有这个功能,不能提前画图
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